[tanna]

assignment 2


Section A:

Find 'x'

1. -2(x + 3) = x + 6

2. -3(-x - 6) = 3x - 23

3.-7(x - 6) - 3x - 3 = 3(x + 5) - 2x

4. -2(x - 6) / 7 - (x - 3) / 2 = - x




Section B:

Find 'x' and 'y'

1. y + x = -3, 3y - 2x = 21

2. 3y - 12x = 15, 2y - 2x = 4

3. y - 4x = 8, x + 2 = 0

4. 3y - 12x = 15, 2y - 2x = 4

5. y + x = -3, 3y - 2x = 21


Section C:

Find the domain of 'x'

1.

2.

3.

4.

5.


Due 24 hours from now.

[tanna]

Time's a wasting Hellzangel.

[HellzAngel]

	Quote:			Originally Posted by tanna
	Time's a wasting Hellzangel.

ouch! the full nick!

assignment 2

Section A:

Find 'x'

1. -2(x + 3) = x + 6: x: -4

2. -3(-x - 6) = 3x - 23 undefined..or sumthin...

3.-7(x - 6) - 3x - 3 = 3(x + 5) - 2x x: 2.18

4. -2(x - 6) / 7 - (x - 3) / 2 = - x : -4.09 ( i dunnoe about this one)




Section B:

Find 'x' and 'y'

1. y + x = -3, 3y - 2x = 21 x: -6 and y: 3

2. 3y - 12x = 15, 2y - 2x = 4 x: -1 and y: 1

3. y - 4x = 8, x + 2 = 0 x: -2 and y: 0

4. 3y - 12x = 15, 2y - 2x = 4 x: -1 and y: 1

5. y + x = -3, 3y - 2x = 21 x: -6 and y: 3

[tanna]

Redo:

4. -2(x - 6) / 7 - (x - 3) / 2 = - x : -4.09

[purple_HAZE]

[color=#454545]Solve each quadratic equation ( Solve for x)

• 7x2 + 14x = 0
• 9x2 - 36 = 0
• 12x3 + 24x2 + 12x = 0
• 121x2 - 264x + 144 = 0
• x2 - 25 = 0
• 4x2 - 20x - 25 = 0
• 16x2 - 400 = 0
• 144x2 - 49 = 0

[/COLOR

// x2 = x square ( x^2)

[tanna]

Purple Haze's assignment is Due 24 hours from now.

[tanna]

Hellzangel, where are you?!?

[purple_HAZE]

there was a sign error in number four which has been fixed - deadline extended by an hour ( i am quite generous )

[HellzAngel]

	Quote:			Originally Posted by purple_HAZE
	( i am quite generous )

no comment

1. x= -2, 2
2.x= 4, -4
3.x= -1, 1
4. x= 12/11, -12/11
5. x= 5, -5
6. x= (i'll come back to this one later..mayb)
7. x= 25, -25
8. x= 7/12, -7/12

[purple_HAZE]

qaudratic, x will have two values! think about it.

if you are still stuck, ask tanna or me.